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Off-topic / Cuh-Cuh-Cuh-Calculus, Cuh-Cuh-Calculus, Muh muh muh Math! >.<

  1. JackyMacky
    Date: Fri, Oct 28 2011 04:09:38

    I don't think there's a Calculus thread so I might as well make one. I sort of need help on this one problem. I'm using this book: Calculus 8th Edition. So I need help on Chapter 3, Section 3.7, problem #26. Please help. :help::bowdown:

  2. shoeman6
    Date: Fri, Oct 28 2011 04:16:05

    Just use calc chat, it has the answers to all the odd problems in that book worked out. http://calcchat.tdlc.com/free_solutions/main.html

  3. JackyMacky
    Date: Fri, Oct 28 2011 04:18:44

    @shoeman6 Ooooooo! Thanks. :lol: EDIT: Actually, that only gives odd problem solutions. -__- I need #26.

  4. funnky
    Date: Fri, Oct 28 2011 04:23:13

    26 is odd when u think about it with math

  5. shoeman6
    Date: Fri, Oct 28 2011 04:26:19

    There are no intercepts, it seems your teacher is a :trollface:

  6. JackyMacky
    Date: Fri, Oct 28 2011 04:32:20

    funnky wrote: 26 is odd when u think about it with math
    You funny-funny. :P

  7. browndog12
    Date: Fri, Oct 28 2011 05:07:41

    a teacher at my school showed me this, i know its false but i cant disprove it D: given n = 0.999... 10n = 9.999... multiply both sides by 10 10n = 9.999... - n = 0.999... create a system of equations with the original equation 9n = 9.0 subtract original equation from modified one n = 1 divide both sides by nine. WTTHFCK

  8. nateiskewl
    Date: Fri, Oct 28 2011 05:09:03

    browndog12 wrote: a teacher at my school showed me this, i know its false but i cant disprove it D: given n = 0.999... 10n = 9.999... multiply both sides by 10 10n = 9.999... - n = 0.999... create a system of equations with the original equation 9n = 9.0 subtract original equation from modified one n = 1 divide both sides by nine. WTTHFCK
    Or if you understand real math... http://upload.wikimedia.org/wikipedia/en/math/6/f/a/6fa510b44742046a167b4b8515162825.png

  9. browndog12
    Date: Fri, Oct 28 2011 12:55:08

    nateiskewl wrote: Or if you understand real math... http://upload.wikimedia.org/wikipedia/en/math/6/f/a/6fa510b44742046a167b4b8515162825.png
    oh sweet jesus

  10. Biji
    Date: Fri, Oct 28 2011 14:52:31

    browndog12 wrote: a teacher at my school showed me this, i know its false but i cant disprove it D: given n = 0.999... 10n = 9.999... multiply both sides by 10 10n = 9.999... - n = 0.999... create a system of equations with the original equation 9n = 9.0 subtract original equation from modified one n = 1 divide both sides by nine. WTTHFCK
    It's not false

  11. JackyMacky
    Date: Fri, Oct 28 2011 22:47:30

    Wtf problems are you doing??!? I specifically said Chapter 3, Section 3.7, problem #26 for the link. -___- We're on the chapter of related rates and optimization. T_T

  12. nateiskewl
    Date: Sat, Oct 29 2011 01:16:04

    JackyMacky wrote: Wtf problems are you doing??!? I specifically said Chapter 3, Section 3.7, problem #26 for the link. -___- We're on the chapter of related rates and optimization. T_T
    Do your own homework you lazy faggot.

  13. JackyMacky
    Date: Sat, Oct 29 2011 22:34:53

    nateiskewl wrote: Do your own homework you lazy faggot.
    I said I needed help, not answers. Technically, I am doing my own homework. What gives you the right to call me a fag, you don't even know what it means. =P

  14. nateiskewl
    Date: Sun, Oct 30 2011 01:52:53

    JackyMacky wrote: I said I needed help, not answers. Technically, I am doing my own homework. What gives you the right to call me a fag, you don't even know what it means. =P
    Yeah, but you're a fag. @AoD1 REQUESTING BACKUP

  15. JackyMacky
    Date: Sun, Oct 30 2011 04:21:15

    nateiskewl wrote: Yeah, but you're a fag.
    Never mind, so be it. <_<

  16. Xero
    Date: Mon, Oct 31 2011 14:13:42

    JackyMacky wrote: Wtf problems are you doing??!? I specifically said Chapter 3, Section 3.7, problem #26 for the link. -___- We're on the chapter of related rates and optimization. T_T
    I hope that this isn't too late, but you need to take the second derivatives to find extrema (max/min). f(x)=x^(1/3) f'(x)=(1/3)*x^(-2/3) f''(x)=(-2/9)*x^(-5/3) http://library.thinkquest.org/3616/Calc/S2/FMME.html More instructions await you here.

  17. JackyMacky
    Date: Tue, Nov 1 2011 01:18:50

    Xero wrote: I hope that this isn't too late, but you need to take the second derivatives to find extrema (max/min). f(x)=x^(1/3) f'(x)=(1/3)*x^(-2/3) f''(x)=(-2/9)*x^(-5/3) http://library.thinkquest.org/3616/Calc/S2/FMME.html More instructions await you here.
    It's too late but thanks. ^_^ Same thing what my teacher showed us. LOL

  18. exclusive
    Date: Sun, Nov 6 2011 07:56:26

    JackyMacky wrote: @shoeman6 Ooooooo! Thanks. :lol: EDIT: Actually, that only gives odd problem solutions. -__- I need #26.
    lol same my text book gives odd solutions too and sometimes even skips like 10 questions in a row