UPSB v4

Off-topic / Basic Chemistry help

  1. SuiXidaL
    Date: Thu, Mar 10 2011 07:57:57

    Reaction A - A small amount of Copper(II) Carbonate is heated in a test tube. It turns black. Reaction B - A small piece of magnesium is is placed a test tube with Nitric acid. It starts to bubble slighty and gasses are produced Reaction C - Nitric acid + sodium hydroxide are placed together in a test tube, the temperature increases by 1 degree./ Reaction D - Dilute barium nitrade + sodium sulfate are added together, a precipitate is formed Reaction E - a small piece of zinc is added into dilute copper(II) sulfate solution, a precipitate is formed I need like explainations of each for a science prac report.

  2. i.suk
    Date: Thu, Mar 10 2011 08:01:02

    ok, we have to find a linear relationship that fulfills/approximately fulfills the set of points given. we know linear equation is in form y = mx + b, where m is gradient etcetc in my solution, i just chose the 2 endpoints of the data given (i.e. x = 1, y = 7 and x = 2.5, y = 11) for my guess --> let (x1, y1) be the point (1 ,7) and (x2, y2) be (2.5, 11) gradient = rise over run (LOL simple maths hahahaha) so; to find gradient, m = (y1 - y2) / (x1 - x2) sub (x1, y1) and (x2, y2) as said previously --> gradient = (11- 7) / (2.5 - 1) = 4/1.5 = 8/3 so m = 8/3. subbing m = 8/3 back into the linear equation form (y = mx + b) we get y = 8x/3 + b to find b, we must sub one of the points of the data given into the x and y of the equation. i picked (1,7) as this point...so sub x = 1 and y = 7 into equation y = 8x/3 + b. we get: 7 = 8/3 + b, so b = 7 - 8/3 = 13/3 so m = 8/3 and b = 13/3 --> therefore a linear equation that approximately satisfies those set of points is y = 8x/3 + 13/3

  3. chogoling
    Date: Thu, Mar 10 2011 08:13:24

    if you're looking for line of best fit, just plug the numbers into an excel graph, it gives you function (type can depend on what you decide on).

  4. nateiskewl
    Date: Thu, Mar 10 2011 14:22:02

    TI-8x calculators do this with ease. Import a list (2nd -> STAT) with the x-values as L1 and the y-values as L2. Then click the STAT button and look for something like LinReg.

  5. Erirornal Kraione
    Date: Thu, Mar 10 2011 18:18:45

    You have to rely on calculators to do that? :P

  6. Awesome
    Date: Thu, Mar 10 2011 18:55:29

    Erirornal Kraione wrote: You have to rely on calculators to do that? :P
    everyone wants the easy way out, then they justify it with how they will "never use it" so why would they actually learn

  7. nateiskewl
    Date: Fri, Mar 11 2011 00:17:02

    Erirornal Kraione wrote: You have to rely on calculators to do that? :P
    It's easy to do without a calculator, but I'm on my iPad and I don't have the patience to right out all the steps.

  8. iMatt
    Date: Fri, Mar 11 2011 01:22:28

    Nate has an iPad. Total Fag.

  9. SJ
    Date: Fri, Mar 11 2011 01:26:32

    He doesn't have the patience to RIGHT out all the steps. Total Fag.

  10. Mr.Squekers
    Date: Fri, Mar 11 2011 01:35:29

    0 1 2 __________________ 3.9 7 10.1 a 3.1 increase. so therefore, y= ....wtf? ok right now im thinking y=3.9x+3.1 but it doesnt work up past 3...

  11. nateiskewl
    Date: Fri, Mar 11 2011 06:17:16

    iMatt wrote: Nate has an iPad. Total Fag.
    Nate got it for free.

  12. SuiXidaL
    Date: Wed, Mar 16 2011 08:11:38

    bump

  13. Biji
    Date: Wed, Mar 16 2011 08:39:55

    A - CuCO3(s) = CuO(s) + CO2(g) CuO is black B - Mg(s) = Mg2+(aq) + 2e 2H+(aq) + 2e = H2(g) Mg(s) + 2H+(aq) = Mg2+ (aq) + H2(g) This is redox H+ comes from the acid(durr) C - H3O+(aq) + HO-(aq) = 2H2O(l) redox, exothermic D - Ba(NO3)2(aq) + Na2SO4(aq) = 2NaNO3(aq) + BaSO4(s) E - Cu2+(aq) + 2e = Cu(s) Zn(s) = Zn2+(aq) + 2e Cu2+(aq) + Zn(s) = Cu(s) + Zn(aq) again, redox

  14. SuiXidaL
    Date: Wed, Mar 16 2011 21:28:06

    Biji wrote: A - CuCO3(s) = CuO(s) + CO2(g) CuO is black B - Mg(s) = Mg2+(aq) + 2e 2H+(aq) + 2e = H2(g) Mg(s) + 2H+(aq) = Mg2+ (aq) + H2(g) This is redox H+ comes from the acid(durr) C - H3O+(aq) + HO-(aq) =H2O(l) redox, exothermic D - Ba(NO3)2(aq) + Na2SO4(aq) = 2NaNO3(aq) + BaSO4(s) E - Cu2+(aq) + 2e = Cu(s) Zn(s) = Zn2+(aq) + 2e Cu2+(aq) + Zn(s) = Cu(s) + Zn(aq) again, redox
    Thanks :D Haha I went off before you posted this answer, so i couldn't thank you D:

  15. hoiboy
    Date: Thu, Mar 17 2011 05:24:43

    Krispy Kreme;72801]Reaction A - A small amount of Copper(II) Carbonate is heated in a test tube. It turns black. Reaction B - A small piece of magnesium is is placed a test tube with Nitric acid. It starts to bubble slighty and gasses are produced Reaction C - Nitric acid + sodium hydroxide are placed together in a test tube, the temperature increases by 1 degree./ Reaction D - Dilute barium nitrade + sodium sulfate are added together, a precipitate is formed Reaction E - a small piece of zinc is added into dilute copper(II) sulfate solution, a precipitate is formed I need like explainations of each for a science prac report.[/QUOTE] [QUOTE=i.suk wrote: ok, we have to find a linear relationship that fulfills/approximately fulfills the set of points given. we know linear equation is in form y = mx + b, where m is gradient etcetc in my solution, i just chose the 2 endpoints of the data given (i.e. x = 1, y = 7 and x = 2.5, y = 11) for my guess --> let (x1, y1) be the point (1 ,7) and (x2, y2) be (2.5, 11) gradient = rise over run (LOL simple maths hahahaha) so; to find gradient, m = (y1 - y2) / (x1 - x2) sub (x1, y1) and (x2, y2) as said previously --> gradient = (11- 7) / (2.5 - 1) = 4/1.5 = 8/3 so m = 8/3. subbing m = 8/3 back into the linear equation form (y = mx + b) we get y = 8x/3 + b to find b, we must sub one of the points of the data given into the x and y of the equation. i picked (1,7) as this point...so sub x = 1 and y = 7 into equation y = 8x/3 + b. we get: 7 = 8/3 + b, so b = 7 - 8/3 = 13/3 so m = 8/3 and b = 13/3 --> therefore a linear equation that approximately satisfies those set of points is y = 8x/3 + 13/3
    LOL I thought i.suk was trolling.

  16. i.suk
    Date: Thu, Mar 17 2011 08:23:47

    hoiboy wrote: LOL I thought i.suk was trolling.
    =__="

  17. pensp
    Date: Thu, Mar 17 2011 17:08:31

    that was the first thing i thought too lol