UPSB v4

Off-topic / maths and stuff

  1. Yanos
    Date: Thu, Aug 30 2012 13:17:01

    (ax+b)(x-1) + c(x^2 +5) = 18 for all real values of x. By substituting suitable values for x, find a,b,c.

  2. Pudels Kern
    Date: Thu, Aug 30 2012 13:42:46

    c=3 a=b=-3

  3. Yamaguchi
    Date: Thu, Aug 30 2012 14:13:35

    Pudels Kern wrote: c=3 a=b=-3
    shocks

  4. i.suk
    Date: Thu, Aug 30 2012 14:35:41

    expand+group --> (a+c) x^2 + (b-a) x - b + 5c = 18 sub x = 0 --> - b + 5c = 18 sub x = 1 --> a + c + b - a - b + 5c = 18 --> 6c = 18 --> c = 3 subbing c = 3 into - b + 5c = 18 --> - b + 15 = 18 --> b = -3 sub x = 2 and b = -3, c = 3 into original equation --> 4(a+3) + 2(-3-a) - b + 5c = 18 --> 4a + 12 - 6 - 2a = 0 --> a = -3 so a = b = -3; c = 3

  5. Xienix
    Date: Thu, Aug 30 2012 15:41:34

    alot to learn i have O.o

  6. Yanos
    Date: Thu, Aug 30 2012 22:41:40

    thanks